
Dictionaries
basketball_champions_top10= {
'Los Angeles Lakers': 17,
'Boston Celtics': 17,
'Golden State Warriors': 7,
'Chicago Bulls': 6,
'San Antonio Spurs': 5,
'Philadelphia 76ers': 3,
'Detroit Pistons': 3,
'Miami Heat': 3,
'New York Knicks': 2,
'Houston Rockets': 2,
'Milwaukee Bucks': 2,
}1. Accessing Dictionaries Elements
# Print out the keys in basketball_champions
print(f"Keys: \n{basketball_champions_top10.keys()}\n")
# Print out the values in basketball_champions
print(f"Values: \n{basketball_champions_top10.values()}\n")
# Print out all key-value pairs with items()
print(f"Items: \n{basketball_champions_top10.items()}\n")
# Print out championship counts for 'Boston Celtics'
print(f"Boston Celtics championships: {basketball_champions_top10['Boston Celtics']}")
#OUTPUT
"""
Keys:
dict_keys(['Los Angeles Lakers', 'Boston Celtics', 'Golden State Warriors', 'Chicago Bulls', 'San Antonio Spurs', 'Philadelphia 76ers', 'Detroit Pistons', 'Miami Heat', 'New York Knicks', 'Houston Rockets'])
Values:
dict_values([17, 17, 7, 6, 5, 3, 3, 3, 2, 2])
Items:
dict_items([('Los Angeles Lakers', 17), ('Boston Celtics', 17), ('Golden State Warriors', 7), ('Chicago Bulls', 6), ('San Antonio Spurs', 5), ('Philadelphia 76ers', 3), ('Detroit Pistons', 3), ('Miami Heat', 3), ('New York Knicks', 2), ('Houston Rockets', 2)])
Boston Celtics championships: 17
"""2. Updating Dictionaries
2.1. Adding new key-value pairs
2.2. Deleting new key-value pairs
3. Dictionary Methods
Method
Description
Conclusion
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